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10000/50 - High Altitude Science

📅 March 10, 2026 👤 scraface

Mar 10, 2026

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Now compute $S(5,2) = 2 \cdot S(4,2) + S(4,1) = 2 \cdot 7 + 1 = 14 + 1...
S(6,3) = 3 \cdot 25 + 15 = 75 + 15 = 90
Thus, the number of ways is $\boxed{90}$.**Question:
Find the length of the shortest altitude in a triangle with sides meas...
First, we calculate the area \( A \) of the triangle using Heron's for...
A = \sqrt{s(s-13)(s-14)(s-15)} = \sqrt{21 \times 8 \times 7 \times 6}
The altitudes \( h_a \), \( h_b \), and \( h_c \) corresponding to sid...
h_a = \frac{2A}{a} = \frac{2 \times 84}{13} = \frac{168}{13} \approx 1...
h_b = \frac{2A}{b} = \frac{2 \times 84}{14} = 12
h_c = \frac{2A}{c} = \frac{2 \times 84}{15} = \frac{168}{15} = 11.2

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