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p(t) = 15t^2 + 30t - High Altitude Science

📅 March 10, 2026 👤 scraface

Mar 10, 2026

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But more carefully: among five consecutive numbers, the minimal guaran...
One multiple of 5 → factor of 5
At least two multiples of 2 (possibly one of which is a multiple of 4)...
Wait: 2 and 4 → \( 2 \times 4 = 8 \), divisible by 8. Another example:...
But sequence 4–8: 4 (div by 4), 6 (div by 2), 8 (div by 8) → divisible...
Even sequence 5–9: 8 → div by 8.
Actually, in any five consecutive integers, there is always a multiple...
Similarly, one divisible by 3, and one divisible by 5.
Thus, the product is divisible by \( 8 \times 3 \times 5 = 120 \).
Is there a larger fixed divisor?

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