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Home » Sea el ancho = \(w\), entonces la longitud = \(w + 150\) - High Altitude Science

Sea el ancho = \(w\), entonces la longitud = \(w + 150\) - High Altitude Science

📅 March 10, 2026 👤 scraface

Mar 10, 2026

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📌 إذن، $z^2 = \frac{1 \pm i\sqrt{3}}{2}$. الجذور التربيعية لـ $\frac{1 + i\sqrt{3}}{2}$ (التي تُعتبر $e^{i\pi/3}$) هي:

📌 z = e^{i\pi/6} \quad \text{و} \quad z = e^{i5\pi/6}

📌 الأجزاء التخيلية هي $\sin \frac{\pi}{6} = \frac{1}{2}$ و $\sin \frac{5\pi}{6} = \frac{1}{2}$. للجذور من $z^2 = \frac{1 - i\sqrt{3}}{2} = e^{-i\pi/3}$, فإن الجذور التربيعية هي:

📌 z = e^{-i\pi/6} \quad \text{و} \quad z = e^{-i5\pi/6}

📌 الأجزاء التخيلية هي $-\frac{1}{2}$ و $-\frac{1}{2}$ على التوالي.لذلك، الجزء التخيلي الأكبر هو $\frac{1}{2} = \sin 30^\circ$.

📌 الإجابة النهائية:** $\boxed{30^\circ}$

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