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Home » The final answer is $\boxed150$. - High Altitude Science

The final answer is $\boxed150$. - High Altitude Science

📅 March 10, 2026 👤 scraface

Mar 10, 2026

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📌 5Question: A civil engineer is designing a drainage system using pipes, each seven units long. If the total length of installed pipe is one more than a multiple of 13, what is the smallest two-digit length (in units) of pipe that satisfies this condition?

📌 Solution: We are looking for the smallest two-digit positive integer $ L $ such that

📌 L \equiv 1 \pmod{13}

📌 and $ L $ is a multiple of 7 (since pipes are seven units long and total length is a sum of such pipes). However, note: the problem states the *total length of installed pipe* is one more than a multiple of 13âso $ L \equiv 1 \pmod{13} $, and $ L $ must be expressible as a sum of multiples of 7. But since individual pipes are 7 units, any valid total length must be a multiple of 7. So we seek the smallest two-digit number $ L $ such that:

📌 L \equiv 1 \pmod{13} \quad ext{and} \quad L \equiv 0 \pmod{7}

📌 L \equiv 0 \pmod{7} \

📌 Use the Chinese Remainder Theorem. Let $ L = 7k $. Substitute into the second congruence:

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- 6b + 12 = 0
- 6b = 0
6b = 48
Thus, the value of $ b $ is $\boxed{8}$.
Question: A science educator designs a learning module where a student...
Solution: To rationalize the denominator of $ \frac{3x + 4}{\sqrt{x} -...
\frac{3x + 4}{\sqrt{x} - 2} \cdot \frac{\sqrt{x} + 2}{\sqrt{x} + 2} =...
= \frac{(3x + 4)(\sqrt{x} + 2)}{x - 4}
Thus, the rationalized form is:
\frac{3x\sqrt{x} + 6x + 4\sqrt{x} + 8}{x - 4}

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