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Home » Thus, the answer is $\boxed221$. - High Altitude Science

Thus, the answer is $\boxed221$. - High Altitude Science

📅 March 10, 2026 👤 scraface

Mar 10, 2026

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📌 Nehmen wir $ y = x^2 $: $ x \mid y $: wahr. $ y \mid x $? $ x^2 \mid x $ â $ x \mid 1 $ â $ |x| = 1 $.

📌 Donutalo: Die Bedingung $ x \mid y \Rightarrow y \mid x $ ist **nur wahr, wenn $ x = 0 $ oder $ |x| = 1 $**.

📌 FÃ¼r $ x = 0 $: $ x \mid y $ nur wenn $ y = 0 $. Dann $ y \mid x $? $ 0 \mid 0 $: wahr. Also PrÃ¤misse wahr. $ x \mid 0 $? wahr â Implikation wahr.

📌 FÃ¼r $ x = 1 $: $ x \mid y \Rightarrow y \mid 1 $ â $ y = \pm1 $, aber $ y \mid 1 $: nur $ y = \pm1 $. $ y \mid x $? $ \pm1 \mid 1 $: wahr â Implikation wahr. $ x \mid 0 $? wahr â Implikation wahr.

📌 FÃ¼r $ x = -1 $: gleich wie $ x = 1 $

📌 FÃ¼r $ x = 5 $: $ y = 10 $: $ 5 \mid 10 $ wahr, $ 10 \mid 5 $? falsch â Implikation falsch â gesamte Aussage falsz

📌 FÃ¼r $ x = 2 $: $ y = 4 $: $ 2 \mid 4 $ wahr, $ 4 \mid 2 $? falsch â Implikation falsz â Aussage falsz

📌 Also: Die Aussage $ orall x,\, \left( orall y,\ (x \mid y \Rightarrow y \mid x)

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